How to Solve Merge Intervals in Python
Struggling with the Merge Intervals problem in Python? This step-by-step guide explains the logic behind interval overlap, shows both brute force and optimal approaches, and walks through a clean implementation with time complexity analysis. If you want to master common coding interview patterns and understand why sorting is critical for interval problems, this tutorial breaks it down clearly and practically.
Table of Contents
Understanding the Merge Intervals Problem
You’re given intervals like:
[[1,3], [2,6], [8,10], [15,18]]Your goal: merge overlapping intervals.
Step 1: Understand the Pattern
If:
Current interval start ≤ previous interval end
They overlap.
Step 2: Brute Force Approach
Compare every interval with every other interval.
Time complexity: O(n²)
This works for small datasets but fails in interviews.
Step 3: Optimal Approach
Sort intervals by start time.
Iterate once.
Merge if overlapping.
Time Complexity: O(n log n)
Python Implementation
def merge(intervals):
intervals.sort(key=lambda x: x[0])
merged = [intervals[0]]
for current in intervals[1:]:
last = merged[-1]
if current[0] <= last[1]:
last[1] = max(last[1], current[1])
else:
merged.append(current)
return mergedWhy Students Fail This Question
Not sorting first
Not understanding interval overlap logic
Forgetting time complexity
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